pat1009—Product of Polynomials
跟前面多项式相加解题思路一致。
This time, you are supposed to find A*B where A and B are two polynomials.
Input Specification:
Each input file contains one test case
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pat1008—Elevator
The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elev
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pat1006—Sign In and Sign Out
At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock th
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pat1005—Spell It Right
Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.
Input Specificat
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pat1002-A+B for Polynomials
继续做吧。题目如下：
This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case
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pat1001-A+B Format
前言：自己平时不玩ACM，保研需要，也做做题目，练练手，C语言也学得不好，C++就直接没学过。浙大复试通知上也是说只能用C或者C++。所以……
下面是pat1001，题目如下：
Calculate a + b and output the sum in standard format —
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实习生工作日志8-29—9-2
感觉这一周没有做什么。因为就等着招聘问答发布。计划30号发布，结果到9月1号才正式发布出去。前两天跟测了下，因为涉及到我的那几个页面比较简单，没有什么bug，于是就做了另外一个需求，替换掉以前的User大对象，做重构吧，把以前的代码重新划分下模块。然后还做了一个产品那边要的数据。1000个用户的二度
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来信——一部很感人的微电影
今天看到了这个视频，挺感人滴。大家经常给家里人打个电话吧。